Optimal. Leaf size=106 \[ -\frac{1}{6} a d^3 \cos (c) \text{CosIntegral}(d x)+\frac{1}{6} a d^3 \sin (c) \text{Si}(d x)+\frac{a d^2 \sin (c+d x)}{6 x}-\frac{a \sin (c+d x)}{3 x^3}-\frac{a d \cos (c+d x)}{6 x^2}+b d \cos (c) \text{CosIntegral}(d x)-b d \sin (c) \text{Si}(d x)-\frac{b \sin (c+d x)}{x} \]
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Rubi [A] time = 0.206963, antiderivative size = 106, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 5, integrand size = 17, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.294, Rules used = {3339, 3297, 3303, 3299, 3302} \[ -\frac{1}{6} a d^3 \cos (c) \text{CosIntegral}(d x)+\frac{1}{6} a d^3 \sin (c) \text{Si}(d x)+\frac{a d^2 \sin (c+d x)}{6 x}-\frac{a \sin (c+d x)}{3 x^3}-\frac{a d \cos (c+d x)}{6 x^2}+b d \cos (c) \text{CosIntegral}(d x)-b d \sin (c) \text{Si}(d x)-\frac{b \sin (c+d x)}{x} \]
Antiderivative was successfully verified.
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Rule 3339
Rule 3297
Rule 3303
Rule 3299
Rule 3302
Rubi steps
\begin{align*} \int \frac{\left (a+b x^2\right ) \sin (c+d x)}{x^4} \, dx &=\int \left (\frac{a \sin (c+d x)}{x^4}+\frac{b \sin (c+d x)}{x^2}\right ) \, dx\\ &=a \int \frac{\sin (c+d x)}{x^4} \, dx+b \int \frac{\sin (c+d x)}{x^2} \, dx\\ &=-\frac{a \sin (c+d x)}{3 x^3}-\frac{b \sin (c+d x)}{x}+\frac{1}{3} (a d) \int \frac{\cos (c+d x)}{x^3} \, dx+(b d) \int \frac{\cos (c+d x)}{x} \, dx\\ &=-\frac{a d \cos (c+d x)}{6 x^2}-\frac{a \sin (c+d x)}{3 x^3}-\frac{b \sin (c+d x)}{x}-\frac{1}{6} \left (a d^2\right ) \int \frac{\sin (c+d x)}{x^2} \, dx+(b d \cos (c)) \int \frac{\cos (d x)}{x} \, dx-(b d \sin (c)) \int \frac{\sin (d x)}{x} \, dx\\ &=-\frac{a d \cos (c+d x)}{6 x^2}+b d \cos (c) \text{Ci}(d x)-\frac{a \sin (c+d x)}{3 x^3}-\frac{b \sin (c+d x)}{x}+\frac{a d^2 \sin (c+d x)}{6 x}-b d \sin (c) \text{Si}(d x)-\frac{1}{6} \left (a d^3\right ) \int \frac{\cos (c+d x)}{x} \, dx\\ &=-\frac{a d \cos (c+d x)}{6 x^2}+b d \cos (c) \text{Ci}(d x)-\frac{a \sin (c+d x)}{3 x^3}-\frac{b \sin (c+d x)}{x}+\frac{a d^2 \sin (c+d x)}{6 x}-b d \sin (c) \text{Si}(d x)-\frac{1}{6} \left (a d^3 \cos (c)\right ) \int \frac{\cos (d x)}{x} \, dx+\frac{1}{6} \left (a d^3 \sin (c)\right ) \int \frac{\sin (d x)}{x} \, dx\\ &=-\frac{a d \cos (c+d x)}{6 x^2}+b d \cos (c) \text{Ci}(d x)-\frac{1}{6} a d^3 \cos (c) \text{Ci}(d x)-\frac{a \sin (c+d x)}{3 x^3}-\frac{b \sin (c+d x)}{x}+\frac{a d^2 \sin (c+d x)}{6 x}-b d \sin (c) \text{Si}(d x)+\frac{1}{6} a d^3 \sin (c) \text{Si}(d x)\\ \end{align*}
Mathematica [A] time = 0.187462, size = 95, normalized size = 0.9 \[ \frac{d x^3 \cos (c) \left (6 b-a d^2\right ) \text{CosIntegral}(d x)+d x^3 \sin (c) \left (a d^2-6 b\right ) \text{Si}(d x)+a d^2 x^2 \sin (c+d x)-2 a \sin (c+d x)-a d x \cos (c+d x)-6 b x^2 \sin (c+d x)}{6 x^3} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.013, size = 102, normalized size = 1. \begin{align*}{d}^{3} \left ({\frac{b}{{d}^{2}} \left ( -{\frac{\sin \left ( dx+c \right ) }{dx}}-{\it Si} \left ( dx \right ) \sin \left ( c \right ) +{\it Ci} \left ( dx \right ) \cos \left ( c \right ) \right ) }+a \left ( -{\frac{\sin \left ( dx+c \right ) }{3\,{d}^{3}{x}^{3}}}-{\frac{\cos \left ( dx+c \right ) }{6\,{d}^{2}{x}^{2}}}+{\frac{\sin \left ( dx+c \right ) }{6\,dx}}+{\frac{{\it Si} \left ( dx \right ) \sin \left ( c \right ) }{6}}-{\frac{{\it Ci} \left ( dx \right ) \cos \left ( c \right ) }{6}} \right ) \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [C] time = 3.41385, size = 166, normalized size = 1.57 \begin{align*} -\frac{{\left ({\left (a{\left (\Gamma \left (-3, i \, d x\right ) + \Gamma \left (-3, -i \, d x\right )\right )} \cos \left (c\right ) + a{\left (-i \, \Gamma \left (-3, i \, d x\right ) + i \, \Gamma \left (-3, -i \, d x\right )\right )} \sin \left (c\right )\right )} d^{5} -{\left (6 \, b{\left (\Gamma \left (-3, i \, d x\right ) + \Gamma \left (-3, -i \, d x\right )\right )} \cos \left (c\right ) - b{\left (6 i \, \Gamma \left (-3, i \, d x\right ) - 6 i \, \Gamma \left (-3, -i \, d x\right )\right )} \sin \left (c\right )\right )} d^{3}\right )} x^{3} + 2 \, b d x \cos \left (d x + c\right ) + 4 \, b \sin \left (d x + c\right )}{2 \, d^{2} x^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.77675, size = 290, normalized size = 2.74 \begin{align*} \frac{2 \,{\left (a d^{3} - 6 \, b d\right )} x^{3} \sin \left (c\right ) \operatorname{Si}\left (d x\right ) - 2 \, a d x \cos \left (d x + c\right ) -{\left ({\left (a d^{3} - 6 \, b d\right )} x^{3} \operatorname{Ci}\left (d x\right ) +{\left (a d^{3} - 6 \, b d\right )} x^{3} \operatorname{Ci}\left (-d x\right )\right )} \cos \left (c\right ) + 2 \,{\left ({\left (a d^{2} - 6 \, b\right )} x^{2} - 2 \, a\right )} \sin \left (d x + c\right )}{12 \, x^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (a + b x^{2}\right ) \sin{\left (c + d x \right )}}{x^{4}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [C] time = 1.19779, size = 1126, normalized size = 10.62 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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